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टेलीग्राम चैनल का लोगो mathongo_iit_jee — MATHONGO OFFICIAL M
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नवीनतम संदेश 10

2022-09-23 15:42:54
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62 views12:42
ओपन / कमेंट
2022-09-23 09:15:58
Are you finding it difficult to manage coaching, school, and hobbies due to too much pressure?

Ye sab ko acche ke karne ke liye apko Resilient hona padega! Kya hota hai Resilient hona?

Ek resilient aur mentally strong aspirant:
Apna focus maintain kar sakta hai!
Social Media aur sari distractions se easily bach sakta hai
Emotions ko acche se pehchan sakta hai
Resilient people are also compassionate toward themselves
Challenges ko positive way mei dekhta hai
Negative thoughts ko acche se deal kar sakta hai

Learn scientific techniques developed by Top IITians, NEETians and curated by psychologists by giving the CQ (Compete Quotient) assessment: https://bit.ly/telegram_CQ

Always with you,
PeakMind
71 views06:15
ओपन / कमेंट
2022-09-23 07:28:35 Most important orders for JEE MAINS and NEET

01. Melting point=
Li > Na > K > Rb > Cs

02. Colour of the flame=
Li-Red, Na-Golden, K-Violet, Rb-Red, Cs-Blue, Ca-Brick red, Sr-Blood red, Ba-Apple green

03. Stability of hydrides =
LiH > NaH > KH > RbH> CsH

04. Basic nature of hydroxides=
LIOH < NaOH < KOH < RbOH < CsOH

05. Hydration energy=
Li> Na > K> Rb > Cs

06. Reducing character=
Li > Cs > Rb > K > Na

07. Stability of +3 oxidation state=
B> Al > Ga > In > T1

08. Stability of +1 oxidation state= Ga < In < TI

09. Basic nature of the oxides and hydroxides=
B< Al< Ga < In < TI

10. Relative strength of Lewis acid= BF3 < BCl3 < BBr3 < BI3

11. Ionisation energy=
B> Al In
12. Reactivity=
C
13. Metallic character=
C< Si < Ge < Sn < Pb

14. Acidic character of the oxides=
Co2 > SiO2 > Ge02 > SnO2 > PbO2

15. Reducing nature of hydrides=
CH4 < SiH4 < GeH4 < SnH4 < PbH4

16. Thermal stability of tetrahalides=
CCl4> SiCl4> GeCl4> SnCl4 > PbCl4

17. Oxidising character of M+4 species=
GeCl4 < SnCl4 < PbCl4

18. Ease of hydrolysis of tetrahalides=
SiCl4 < GeCl4 < SnCl4 < PbCI4

19. Acidic strength of trioxides=
N203 > P2O3 > As2O3

20. Acidic strength of pentoxides=
N2O2 > P2O2> As202 > Sb2O2 > Bi‌202

21. Acidic strength of oxides of nitrogen=
N2O < NO
22. Basic nature/ bond angle/ thermal stability and dipole moment of hydrides=
NH3 > PH3 > AsH3 > SbH3 > BiH3

23. Stability of trihalides of nitrogen=
NF3 > NCl3 > NBr3

24.Lewis base strength=
NF3
25. Ease of hydrolysis of trichlorides=
NCl3 > PCI3 > AsCl3 > SbCl3 > BiCl3

26. Lewis acid strength of trihalides of P, As, and Sb=
PCl3 > ASCl3 > SbCl3

27. Lewis acid strength among phosphorus trihalides
PF3 > PCl3 > PBr3 > PI3

28. Melting and boiling point of hydrides=
H2O > H2Te > H2Se >H2S

29. Volatility of hydrides=
H2O < H2Te < H2Se < H2S

30. Reducing nature of hydrides=
H2S < H2Se < H2Te

31. Covalent character of hydrides=
H2O < H2S < H2Se < H2Te

32. The acidic character of oxides (elements in the same oxidation state)=
SO2 > SeO2 > TeO2 > PoO2
SO3 > SeO3 > TeO3

33. Acidic character of oxide of a particular element (e.g. S)=
SO < SO2 < SO3
SO2 > TeO2 > SeO2 > PoO2

34. Bond energy of halogens=
Cl2 > Br2 > F2 > I2

35. Solubility of halogen in water =
F2 > Cl2 > Br2 > I2

36. Oxidising power=
F2 > Cl2 > Br2 > I2

37. Enthalpy of hydration of X ion=
F- > Cl- > Br- >I-

38. Reactivity of halogens:=
F> Cl> Br > I

39. Ionic character of M-X bond in halides
= M-F > M-Cl > MBr > M-I

40. Reducing character of X ion:=
I- > Br- > Cl- > F-

41. Acidic strength of halogen acids=
HI > HBr > HCI > HF

42. Reducing property of hydrogen halides
= HF < HCL < HBr < HI

43. Oxidising power of oxides of chlorine
= Cl2O > ClO2 > Cl206 > Cl2O7

44. Decreasing ionic size=
02- > F- > Na+ > Mg2+

45. Increasing acidic property=
Na2O3 < MgO < ZnO< P205

46. Increasing bond length=
N2 <02 < F2 < CL2

47. Increasing size=
Ca2+ < Cl- < S2-

48. Increasing acid strength=
HClO < HClO2 < HClO3 < HClO4

49. Increasing oxidation number of iodine=
HI< I2
50. Increasing thermal stability=
HOCl < HOClO < HOClO2 < HOClO3

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60 views04:28
ओपन / कमेंट
2022-09-22 18:54:30
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ओपन / कमेंट
2022-09-22 13:50:18
Are you finding it difficult to manage coaching, school, and hobbies due to too much pressure?

Ye sab ko acche ke karne ke liye apko Resilient hona padega! Kya hota hai Resilient hona?

Ek resilient aur mentally strong aspirant:
Apna focus maintain kar sakta hai!
Social Media aur sari distractions se easily bach sakta hai
Emotions ko acche se pehchan sakta hai
Resilient people are also compassionate toward themselves
Challenges ko positive way mei dekhta hai
Negative thoughts ko acche se deal kar sakta hai

Learn scientific techniques developed by Top IITians, NEETians and curated by psychologists by giving the CQ (Compete Quotient) assessment: https://bit.ly/telegram_CQ

Always with you,
PeakMind
82 views10:50
ओपन / कमेंट
2022-09-22 08:57:55 Notes on Kinetic Theory of Gases

Kinetic Theory of Matter:-

(a) Solids:- It is the type of matter which has got fixed shape and volume. The force of attraction between any two molecules of a solid is very large.
(b) Liquids:- It is the type of matter which has got fixed volume but no fixed shape. Force of attraction between any two molecules is not that large as in case od solids.
(c) Gases:- It is the type of matter does not have any fixed shape or any fixed volume.

Ideal Gas:- A ideal gas is one which has a zero size of molecule and zero force of interaction between its molecules.

Ideal Gas Equation:- A relation between the pressure, volume and temperature of an ideal gas is called ideal gas equation.
PV/T = Constant or PV = nRT
Here, n is the number of moles and R is the universal gas constant.

Gas Constant:-

(a) Universal gas constant (R):-
R= P0 V0/T0
=8.311 J mol-1K-1

(b) Specific gas constant (r):-
PV= (R/M) T = rT,
Here, r = R/M

Real Gas:-The gases which show deviation from the ideal gas behavior are called real gas.

Vander wall’s equation of state for a real gas:-

[P+(na/V)2?][V-nb] = nRT
Here n is the number of moles of gas.

Avogadro’s number (N):- Avogadro’s number (N), is the number of carbon atoms contained in 12 gram of carbon-12.

N = 6.023×10^23

(a) To calculate the mass of an atom/molecule:-

Mass of one atom = atomic weight (in gram)/N
Mass of one molecule = molecular weight (in gram)/N

(b) To calculate the number of atoms/molecules in a certain amount of substance:-

Number of atoms in m gram = (N/atomic weight)×m
Number of molecules in m gram = (N/molecular weight)×m

(c) Size of an atom:-

Volume of the atom, V = (4/3)πr3
Mass of the atom, m = A/N
Here, A is the atomic weight and N is the Avogadro’s number.
Radius, r =[3A/4πNρ]1/3\
Here ρ is the density.

Gas laws:-

Graph Between Pressure and Volume for Boyle's Law(a)

Boyle’s law:- It states that the volume of a given amount of gas varies inversely as its pressure, provided its temperature is kept constant.

PV = Constant

(b) Charles law or Gey Lussac’s law:- It states that volume of a given mass of a gas varies directly as its absolute temperature, provided its pressure is kept constant.

Graph Between Volume and Temperature for Charles LawV/T= Constant

V–V0/V0t = 1/273 = γp

Here γp (=1/273) is called volume coefficient of gas at constant pressure.

Volume coefficient of a gas, at constant pressure, is defined as the change in volume per unit volume per degree centigrade rise of temperature.

(c) Gay Lussac’s law of pressure:- It states that pressure of a given mass of a gas varies directly as its absolute temperature provided the volume of the gas is kept constant.

P/T = P0/T0 or P – P0/P0t = 1/273 = γp

Here γp (=1/273) is called pressure coefficient of the gas at constant volume.

Pressure coefficient of a gas, at constant volume, is defined as the change in pressure per unit pressure per degree centigrade rise of temperature.

(d) Dalton’s law of partial pressures:-

Partial pressure of a gas or of saturated vapours is the pressure which it would exert if contained alone in the entire confined given space.

P= p1+p2+p3+……..

nRT/V = p1+p2+p3+……..

(e) Grahm’s law of diffusion:- Grahm’s law of diffusion states that the rate of diffusion of gases varies inversely as the square root of the density of gases.

R∝1/√ρ or R1/R2 =√ρ2/ ρ1

So, a lighter gas gets diffused quickly.

(f) Avogadro’s law:- It states that under similar conditions of pressure and temperature, equal volume of all gases contain equal number of molecules.

For m gram of gas, PV/T = nR = (m/M) R

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80 views05:57
ओपन / कमेंट
2022-09-21 17:03:32
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ओपन / कमेंट
2022-09-21 08:45:42 Not good in organic chemistry, we have sorted a method only for you.
93 views05:45
ओपन / कमेंट
2022-09-21 08:45:41
Organic Chemistry ho ya difficult formulae! Aap easy way mei yad car sakte hai ki aap kabhi bhule na!

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82 views05:45
ओपन / कमेंट
2022-09-21 08:37:26 Notes on Inheritance and Variation [[[[[PART-3]]]]]

✓✓✓✓✓✓✓✓✓✓✓✓✓✓

Numerical aberrations of chromosomes:

Each species has a characteristic number of chromosome.

Variations or numerical changes in chromosomes (Heteroploidy) can be mainly of two types:

(1) Euploidy:

The somatic chromosome number in euploids is the exact multiple of basic haploid number. In euploidy an organism acquires an additional set of chromosomes over and above the diploid complement.

(a) Monoploidy or haploidy:

Monoploids possess only one set or single basic set of chromosomes. Haploids on the other hand have half the somatic chromosome number. In diploid organisms monoploids and haploids are identical while in a tetra-or hexaploid with 4n or 6n chromosomes the haploids will possess 2n or 3n chromosome whereas its monoploid will possess only one set (n) of chromosome.

(b) Diploidy:

The common chromosome number in the somatic cells of plants and animals.

(c) Polyploidy:

Organism with more than two sets of chromosomes are known as polyploids. It may be triploid with three sets of chromosomes (3n) or tetraploid with four sets of chromosome (4n) and so on.

(2) Aneuploidy:

Aneuploidy is the term applied for the chromosomal mutations involving only a part of a set, i.e., loss (hypoploidy) or addition (hyperploidy) of one or more chromosomes. Aneuploidy may result from non disjunction of chromosome during cell division.

(a) Monosomy:

Diploid organism that are missing one chromosome of a single pair with genomic formula 2n – 1. Monosomics can form two kinds of gametes, (n) and (n –1).

(b) Nullisomy:

An organism that has lost a chromosome pair is nullisomic. The result is usually lethal to diploids (2n – 2).

(c) Trisomy:

Diploids which have extra chromosome represented by the chromosomal formula 2n + 1. One of the pairs of chromosomes has an extra member, so that a trivalent may be formed during meiotic prophase.

(d) Tetrasomy:

In tetrasomic individual particular chromosome of the haploid set is represented four times in a diploid chromosomal complement. The general chromosomal formula for tetrasomics is 2n + 2 rather than 2n + 1+ 1. The formula 2n + 1 + 1 represents a double trisomic.

Types of aneuploidy:

Aneuploidy may be of following types on the basis of chromosomes involved in non disjunction.

(a) Aneuploidy involving non-disjunction in sex chromosomes: This kind of aneuploidy is brought about due to non-disjunction in sex chromosomes. It may lead to following types of syndromes:

(1) Turner’s syndrome:

Such persons are monosomic for sex chromosomes i.e. possess only one X and no Y chromosome (XO). In other words they have chromosome number 2n – 1 = 45. They are phenotypic females but are sterile because they have under developed reproductive organs. They are dwarf about 4 feet 10 inches and are flat chested with wide spread nipples of mammary glands which never enlarge like those in normal woman. They develop as normal female in childhood but at adolescence their ovaries remain under developed. They lack female hormone estrogen. About one out of every 5,000 female births results in Turner’s syndrome.

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74 views05:37
ओपन / कमेंट