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नवीनतम संदेश 13
2021-11-09 11:56:26
132*40=5280
Pass=42*x
Fail=(132-x)*20=2640-20x
5280=42x+2640-2x
X=2640/22
X=120
Pass
120*40=5040
Fail=(132-120)*20=240
5040:240
504:24
21:1
46 views.RÀdhà, 08:56
2021-11-09 11:56:26
Please solve 9
43 views.RÀdhà, 08:56
2021-11-08 17:19:10
52 views.RÀdhà, 14:19
2021-11-08 17:19:10
52 views.RÀdhà, 14:19
2021-11-07 17:31:44
82 views.RÀdhà, 14:31
2021-11-07 17:31:44
74 views.RÀdhà, 14:31
2021-11-07 11:02:09
71 views°•✮•° Virat °•✮•°, 08:02
2021-11-07 11:02:09
Soln explain
67 views°•✮•° Virat °•✮•°, 08:02
2021-11-07 10:22:24
A=5/2(k-40) B=7/2(k-20) C=17/9(k-10) Add all 5/2(k-40)+7/2(k-20)+17/9(k-10)=600 After solving this u will get K=100 A=5/2(k-40) 5/2(100-40) 150,
62 viewsShiva Kashyap, 07:22
2021-11-07 10:22:06
A=5/2(k-40)
B=7/2(k-20)
C=17/9(k-10)
Add all
5/2(k-40)+7/2(k-20)+17/9(k-10)=600
After solving this u will get
K=100
A=5/2(k-40)
5/2(100-40)
150,
62 viewsGarïmä, 07:22
A
